2x^2+34=20x-16

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Solution for 2x^2+34=20x-16 equation: 



2x^2+34=20x-16

We move all terms to the left:

2x^2+34-(20x-16)=0

We get rid of parentheses

2x^2-20x+16+34=0

We add all the numbers together, and all the variables

2x^2-20x+50=0

a = 2; b = -20; c = +50;
Δ = b2-4ac
Δ = -202-4·2·50
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{20}{4}=5$

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